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5y^2-33y+52=0
a = 5; b = -33; c = +52;
Δ = b2-4ac
Δ = -332-4·5·52
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-7}{2*5}=\frac{26}{10} =2+3/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+7}{2*5}=\frac{40}{10} =4 $
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